Q. The probability of forming a three digit numbers with the same digits when three digit numbers are formed out of the digit 0, 2, 4, 6, 8 is
A) $\frac{1}{16}$
B) $\frac{1}{12}$
C) $\frac{1}{645}$
D) $\frac{1}{25}$
Explanation
(d)
Total number of cases$= 4 \times 5 \times 5 = 100$
Favourable cases are 222, 444, 666, 888
Number of favourable cases$= 4$
$\therefore$ Required probability$= \frac{4}{100} = \frac{1}{25}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.