Q. A pair of a dice thrown, if 5. appears on at least one of the dice, then the probability that the sum is 10 or greater, is
A) $\frac{11}{36}$
B) $\frac{2}{9}$
C) $\frac{3}{11}$
D) $\frac{1}{12}$
Explanation
(d)
Favourable cases of getting 10 or greater than 10, if 5 appears on atleast one of dice.
$= \{(5,\ 6),\ (6,\ 5),\ (5,\ 5)\}$
Number of favourable cases =3
Total number of cases = 36
$\therefore$ Required probability $= \frac{3}{36} = \frac{1}{12}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.