Q. Three coins are tossed, then what is the probability that at least two heads appears on upper face?
A) $\frac{5}{8}$
B) 40
C) $\frac{8}{5}$
D) None of these
Explanation
(d)
Here, $n(S) = 2^{3} = 8$
and $E = \{ HTH,HHT,THH,HHH\}$
and $n(E) = 4$
$\therefore$ Required probability $= \frac{n(E)}{n(S)} = \frac{4}{8} = \frac{1}{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.