Q. Two cards are drawn one by one from a pack of cards. The probability of getting first card an ace and second a coloured one is (before drawing second card first card is not placed again in the pack)
A) 1/26
B) 5/52
C) 5/221
D) 4/13
Explanation
(c)
Probability of getting an ace
$P\left( E_{1} \right) = \frac{4}{52} = \frac{1}{13},\ P\left( \frac{E_{2}}{E_{1}} \right) = \frac{15}{51} = \frac{5}{17}$
$P\left( E_{1} \cap E_{2} \right) = P\left( E_{1} \right) \bullet P\left( \frac{E_{2}}{E_{1}} \right)$
$= \frac{1}{13} \bullet \frac{5}{17} = \frac{5}{221}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.