(b)
Let total number of students be 100 in which 60% girls and 40% boys.
Number of boys =40,number of girls =60
25% of boys offer Mathematics $= \frac{25}{100} \times 40 = 10$ boys
10% girls offer Mathematics $= \frac{10}{100} \times 60 = 6$ girls
It means, 16 students offer Mathematics.
$\therefore$ Required probability $= \frac{6}{16} = \frac{3}{8}$