Q. If $4P(A) = 6P(B) = 10P(A \cap B) = 1,$ then$P\left( \frac{B}{A} \right)$ is equal to
A) $\frac{2}{5}$
B) $\frac{3}{5}$
C) $\frac{7}{10}$
D) $\frac{19}{60}$
Explanation
(a)
Given, $4P(A) = 6P(B) = 10P(A \cap B) = 1$
$\therefore\ P\left( \frac{B}{A} \right) = \frac{P(A \cap B)}{P(A)} = \frac{\frac{1}{10}}{\frac{1}{4}} = \frac{2}{5}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.