(b) Required probability$= \ ^{7}C_{2}\left( \frac{1}{6} \right)^{2}\left( \frac{5}{6} \right)^{5} \times \frac{1}{6}$ $= \frac{\ ^{7}C_{2} \times 5^{5}}{6^{8}}$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.