Q. In a college 25% boys and 10% girls offer Mathematics. There are 60% girls in the college. If a Mathematics student is chosen at random, then the probability that the student is a girl, will be
A) $\frac{1}{6}$
B) $\frac{3}{8}$
C) $\frac{5}{8}$
D) $\frac{5}{6}$
Explanation
(b)
Let the total number of students be 100, then in which 60 girls and 40 boys
$As\ 25\%\ of\ boys\ offer\ Mathematics = \frac{25}{100} \times 40 = 10\ boys$
$and\ 10\%\ of\ girls\ offer\ Mathematics = \frac{10}{100} \times 60 = 6\ girls$
$\therefore\$Total number of students, whose offers Mathematics is 16
$\therefore Required\ probability = \frac{6}{16} = \frac{3}{8}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.