Q. In a binomial distribution the probability of getting a success is $1/4$ and standard deviation is 3, then its mean is

A) 6
B) 8
C) 12
D) 10
Explanation

(c)
Given that, probability of success $p = \frac{1}{4}$ and probability of unsuccess $q = \frac{3}{4}$
$\therefore Mean = np$
and standard deviation $= \sqrt{variance}$
$\Rightarrow 3 = \sqrt{Variance}$
$\Rightarrow$ variance = 9
$\Rightarrow npq = 9$
$\Rightarrow n \bullet \frac{1}{4} \bullet \frac{3}{4} = 9$
$\Rightarrow n = \frac{9 \bullet 4 \bullet 4}{3}\ \Rightarrow n = 48$
$\therefore Mean = np = \frac{1}{4} \times 48 = 12$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.