(d) $P$ (selecting a black ball) $= \frac{{\ ^{5}C}_{1}}{{\ ^{12}C}_{1}}$ $P$ (selecting a red ball)$= \frac{{\ ^{3}C}_{1}}{{\ ^{12}C}_{1}}$ $P$ (black ball or red ball) $= \frac{{\ ^{5}C}_{1} + {\ ^{3}C}_{1}}{{\ ^{12}C}_{1}} = \frac{2}{3}$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.