Q. 6 boys and 6 girls sit in a row randomly. The probability that all 6 girls sit together, is
A) $\frac{1}{64}$
B) $\frac{1}{8}$
C) $\frac{1}{132}$
D) None of these
Explanation
(c)
Assuming all six girls as one unit.
$\therefore\ \$Required probability $= \frac{7!\ 6!}{12!} = \frac{1}{132}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.