The probability that a number $n$ chosen at random from 1 to 30, to satisfy $n + (50/n) 27$ is

Question

The probability that a number $n$ chosen at random from 1 to 30, to satisfy $n + (50/n) > 27$ is

Dr. Abubacker · Accepted Answer

(d)
Total outcomes=30
Now, $n + \left( \frac{50}{n} ight) > 27$
$\Rightarrow n^{2} - 27n + 50 > 0$
$\Rightarrow (n - 2)(n - 25) > 0$
Favourable outcomes are 1,26,27,28,29,30
Number of favourable outcomes=6
$	herefore$ Required probability$= \frac{6}{30} = \frac{1}{5}$

Q. The probability that a number $n$ chosen at random from 1 to 30, to satisfy $n + (50/n) > 27$ is

Explanation

Reviewed by Dr. Abubacker

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