Q. The probability that the same number appear on throwing three dice simultaneously, is
A) $\frac{1}{36}$
B) $\frac{5}{36}$
C) $\frac{1}{6}$
D) $\frac{4}{13}$
Explanation
(a)
Total number of favorable cases =6
Total number of cases =216
$\therefore$ Required probability$\ = \frac{6}{216} = \frac{1}{36}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.