Q. When three dice are thrown the probability of getting 4 or 5 on each of the dice simultaneously, is
A) $\frac{1}{72}$
B) $\frac{1}{108}$
C) $\frac{1}{24}$
D) None of these
Explanation
(d)
Total number of cases$= 6^{3} = 216$
Favorable cases are (4,4,5),(4,5,4),(5,4,4),(4,5,5),(5,4,5),(5,5,4),(5,5,5),(4,4,4,).
$\therefore$Total number of cases=8
$\therefore$Required probability$= \frac{8}{216} = \frac{1}{27}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.