Q. The probability that the same number appear on throwing three dice simultaneously, is
A) 1/6
B) 1/36
C) 5/36
D) None of these
Explanation
(b)
Total number of ways $= 6 \times 6 \times 6$
Favourable number of ways = 6
$\therefore\$Required probability $= \frac{6}{6 \times 6 \times 6} = \frac{1}{36}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.