Q. From a pack of cards two are accidently dropped. Probability that they are of opposite shade is
A) $\frac{13}{51}$
B) $\frac{1}{52 \times 51}$
C) $\frac{26}{51}$
D) None of these
Explanation
(c)
$P$(getting 2 different coloured cards)
$= \frac{\ ^{26}C_{1} \times \ ^{26}C_{1}}{\ ^{52}C_{2}}$
$= \frac{26 \times 26 \times 2}{52 \times 51} = \frac{26}{51}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.