(b) Let $S = \{ BBB,\ BBG,\ BGB,\ GBB,\ GGB,\ GBG,\ BGG,\ GGG\}$ and $E = \left\{ BBB,\ BBG,\ BGB,\ GBB,\ GGB,\ GBG,\ BGG \right\}$ $\therefore P(E) = \frac{n(E)}{n(S)} = \frac{7}{8}$
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Ph.D. in Physics with 19+ years of teaching experience.