(a)
Probability of getting a head $= \frac{1}{2}$
$ie,\ p = \frac{1}{2}\ \Rightarrow q = \frac{1}{2}$
$\therefore$ Required probability ${{= \ }^{10}C}_{5}\left( \frac{1}{2} \right)^{5}\left( \frac{1}{2} \right)^{5}$
$= \frac{10 \times 9 \times 8 \times 7 \times 6}{5 \times 4 \times 3 \times 2}\ \left( \frac{1}{2} \right)^{10} = \frac{63}{256}$