Q. Among 15 players, 8 are batsman and 7 are bowlers. The probability that a team is chosen of 6 batsman and 5 bowlers, is
A) $\frac{{\ ^{8}C}_{6} \times {\ ^{7}C}_{5}}{{\ ^{15}C}_{11}}$
B) $\frac{{\ ^{8}C}_{6} + {\ ^{7}C}_{5}}{{\ ^{15}C}_{11}}$
C) $\frac{15}{28}$
D) None of these
Explanation
(a)
Total number of ways of selecting 11 players $=^{15}C_{11}$
Favourable cases $= {\ ^{8}C}_{6} \times^{7}C_{5}$
$\therefore$ Required probability $= \frac{{\ ^{8}C}_{6} \times^{7}C_{5}}{{\ ^{15}C}_{11}}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.