Q. If $A\ and\ B$ are arbitrary events, then
A) $P(A \cap B) \geq P(A) + P(B)$
B) $P(A \cup B) \leq P(A) + P(B)$
C) $P(A \cap B) = P(A) + P(B)$
D) None of the above
Explanation
(b)
We know, $P(A \cup B) = P(A) + P(B) - P(A \cap B) \leq P(A) + P(B)$ $\ \lbrack\because P(A \cap B) \geq 0\rbrack$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.