Q. Unbiased die is thrown, probability that outcome is greater than 4, is
A) $\frac{3}{4}$
B) $\frac{4}{5}$
C) $\frac{1}{3}$
D) $\frac{5}{6}$
Explanation
(c)
$S = \{ 1,2,3,4,5,6\}$ and $E = \{ 5,6\}$
$\therefore\ n(S) = 6\ and\ n(E) = 2$
$\therefore$ Required probability $= \frac{n(E)}{n(S)} = \frac{2}{6} = \frac{1}{3}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.