Q. A man and his wife appear for an interview for two posts. The probability of the man’s selection is 1/5 and that of his wife’s selection is 1/7. The probability that at least one of them is selected, is
A) $\frac{9}{35}$
B) $\frac{12}{35}$
C) $\frac{2}{7}$
D) $\frac{11}{35}$
Explanation
(d)
$P(A \cup B) = P(A) + P(B) - P(AB)$
$P(A \cup B) = P(A) + P(B) - P(A) \bullet P(B)$
$(A\ and\ B$ are independents events)
$= \frac{1}{5} + \frac{1}{7} - \frac{1}{35} = \frac{11}{35}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.