Q. If three students $A,B,C$ can solve a problem with probabilities $\frac{1}{3},\frac{1}{4}$ and $\frac{1}{5}$ respectively, then the probability that the problem will be solved is

A) $\frac{3}{5}$
B) $\frac{4}{5}$
C) $\frac{2}{5}$
D) $\frac{47}{60}$
Explanation

(a)
Given, the probability of solving the problem are $\frac{1}{3}\ ,\frac{1}{4}\ and\frac{1}{5}$ respectively and$\$
corresponding probabilities of not solving the problem are $\frac{2}{3}\ ,\frac{3}{4}\ and\ \frac{4}{2}$ respectively
$\therefore Required\ probability = 1 - P(not\ solving\ the\ problem)$
$= 1 - \left( \frac{2}{3} \times \frac{3}{4} \times \frac{4}{5} \right)$
$= 1 - \frac{2}{5} = \frac{3}{5}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.