Q. A coin and six faced die. Both unbiased, are thrown simultaneously. The probability of getting a head on the coin and an odd number on the die, is
A) $\frac{1}{2}$
B) $\frac{3}{4}$
C) $\frac{1}{4}$
D) $\frac{2}{3}$
Explanation
(c)
Let $E =$Event of getting a head from a coin
$F =$Event of getting an odd number {1, 3,5}, from a die
$P(E) = \frac{1}{2},\ P(F) = \frac{3}{6} = \frac{1}{2}$
Since, $E$ and $F$ are independent events
$\therefore\ P(E \cap F) = P(E) \cap P(F) = \frac{1}{2} \times \frac{1}{2} = \frac{1}{4}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.