(a)
We know, $P(A \cup B) = P(A) + P(B) - P(A \cap B)$
$\frac{5}{6} = \frac{1}{3} + \frac{1}{2} - \ P(A \cap B)$
$\Rightarrow \frac{5}{6} = \frac{5}{6} - P(A \cap B)$
$\Rightarrow \ P(A \cap B) = 0$
$\therefore$ Events $A\ and\ B$ are mutually exclusive.