Q. Given two mutually exclusive events $A\ and\ B$ such that $P(A) = 0.45\ and\ P(B) = 0.35,\ P(A \cap B)$ is equal to
A) $\frac{63}{400}$
B) 0.8
C) $\frac{63}{200}$
D) 0
Explanation
(d)
$P(A) = 0.45,$
$P(B) = 0.35$ (events are mutually exclusive)
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$P(A \cap B) = 0$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.