Q. A coin is tossed three times. The probability of getting a head once and a tail twice is
A) $\frac{1}{8}$
B) $\frac{1}{3}$
C) $\frac{3}{8}$
D) $\frac{1}{2}$
Explanation
(c)
Total number of outcomes=8
Favorable cases are $HTT,THT,TTH$
$\therefore$ Number of favourable outcomes =3
$\therefore$ Required probability$= \frac{3}{8}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.