(b) Let $f(x) = \cos{x,\ f^{'}(x) = \sin x}$ $\Rightarrow \ {\ f}^{''}(x) = \ - \cos x$ $\Rightarrow \ f^{'''}(x) = \sin x$ Since, $\sin{x\ }$is an odd function. $\therefore\ \ f^{'''}$ is an odd function.
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