If $x = A\cos{4t + B\sin{4t,\ \ \ then\frac{d^{2}x}{dt^{2}}\ }}$is equal to

Question

Dr. Abubacker · Accepted Answer

(a)
Here, $x = A\ cos\ 4t + B\ sin\ 4t$
$\Rightarrow \ \frac{dx}{dt} = \  - 4A\sin{4t + 4B\cos{4t}}$
$\Rightarrow \ \frac{d^{2}x}{dt^{2}} = \  - 16\ A\cos\ 4t - 16\ B\sin{4t}$
$\Rightarrow \ \frac{d^{2}x}{dt^{2}} = \  - 16x$

Q. If $x = A\cos{4t + B\sin{4t,\ \ \ then\frac{d^{2}x}{dt^{2}}\ }}$is equal to

Explanation

Reviewed by Dr. Abubacker

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