Q. If $y = {(\cos{x^{2})}}^{2},$ then $\frac{dy}{dx}\$is equal to
A) $- 4x\ sin\ 2x^{2}$
B) $- x\sin x^{2}$
C) $- 2x\sin{2x^{2}}$
D) $- x\cos{2x^{2}}$
Explanation
(c)
$y = {(\cos{x^{2})}}^{2}$
On differentiating w.r.t. $x$, we get
$\ \ \frac{dy}{dx} = 2\cos{x^{2}\ ( - \sin{x^{2})2x = - 2x\sin{2x^{2}}}}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.