Q. If $y = 2^{\log x},\ then\frac{dy}{dx}\$is
A) $\frac{2^{\log x}}{\log 2}$
B) $2^{\log x}.\log 2$
C) $\frac{2^{\log x}}{x}$
D) $\frac{2^{\log x}.\log 2}{x}$
Explanation
(d)
Given $y = 2^{\log x}$
$\Rightarrow \ \frac{dy}{dx} = \ 2^{\log x}.\log_{e}{2.\frac{1}{x}}$
$\Rightarrow \ \frac{dy}{dx} = \frac{2^{\log x}.\log_{e}2}{x}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.