If $x = \frac{2at}{1 + t^{3}}\ and\ y = \frac{2at^{2}}{\left( 1 + t^{3} \right)^{2}},\ then\frac{dy}{dx}\$is

Question

Dr. Abubacker · Accepted Answer

(c)
$\because\ x = \frac{2at}{1 + t^{3}}\ \ and\ \ y = \frac{2{at}^{2}}{\left( 1 + t^{3} ight)^{2}}$
$	herefore 2ay = x^{2}$
$\Rightarrow \frac{dy}{dx} = \frac{x}{a}$

Q. If $x = \frac{2at}{1 + t^{3}}\ and\ y = \frac{2at^{2}}{\left( 1 + t^{3} \right)^{2}},\ then\frac{dy}{dx}\$is

Explanation

Reviewed by Dr. Abubacker

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