(b) Let $f(x) = x^{2}$ On differentiating w.r.t. $x$, we get $f^{'}(x) = 2x$ Given that, $f^{'}(a + b) = f^{'}(a) + f^{'}(b)$ $\Rightarrow 2(a + b) = 2a + 2b$ $\Rightarrow 2a + 2b = 2a + 2b$
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