If $y = an^{- 1}\ x + \cot^{- 1}\ x + \sec^{- 1} + {cosec}^{- 1}\ x,\$then $\frac{dy}{dx}$ is equal to

Question

If $y = 	an^{- 1}\ x + \cot^{- 1}\ x + \sec^{- 1} + {cosec}^{- 1}\ x,\$then $\frac{dy}{dx}$ is equal to

Dr. Abubacker · Accepted Answer

(c)
$y = 	an^{- 1}{x + \cot^{- 1}{x + \sec^{- 1}{x + {cosec}^{- 1}x}}}$
$= \ \frac{\ \pi}{2} + \frac{\pi}{2} = \pi$
$\frac{dy}{dx}\  = \$0