Q. If $y = \sin^{- 1}{\frac{x}{2} + \cos^{- 1}\frac{x}{2},\ then\ the\ value\ of\ \frac{dy}{dx}\ is\ }$
A) 1
B) $- 1$
C) 0
D) 2
Explanation
(c)
Since, $y = \sin^{- 1}{\frac{x}{2} + \cos^{- 1}{\frac{x}{2} = \frac{\pi}{2}}}$
$\therefore\frac{dy}{dx} = 0$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.