Q. If $f(x) = \frac{1}{1 - x},$ then the derivative of the composite function $f\lbrack f\left\{ f(x) \right\}\rbrack$ is equal to

A) 0
B) $\frac{1}{2}$
C) 1
D) 2
Explanation

(c)
$\ f\left\lbrack f\left( f(x) \right) \right\rbrack = f\left\lbrack f\left( \frac{1}{1 - x} \right) \right\rbrack = f\left( \frac{1}{1 - \frac{1}{1 - x}} \right)\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \$
$\left\lbrack \because f(x) = \frac{1}{1 - x} \right\rbrack$
$= f\left( \frac{1 - x}{- x} \right) = \frac{1}{1 + \left( \frac{1 - x}{x} \right)}$
$\Rightarrow \ f\left\lbrack f\left( f(x) \right) \right\rbrack =$ $x$
$\therefore\ \$ The derivative of composite function is equal to 1.

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.