Q. If $y = \left( 1 + x^{2} \right)\tan^{- 1}{x - x,then\ \frac{dy}{dx}}$ is equal to
A) $\tan^{- 1}x$
B) $2x\tan^{- 1}x$
C) $2x\tan^{- 1}{x - 1}$
D) $\frac{2x}{\tan^{- 1}x}$
Explanation
The correct answer is Option B: $2x\tan^{- 1}x$.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.