If $\sin{(x + y) + \cos(x + y) = \log{(x + y),\ \ \ then\frac{d^{2}y}{dx^{2}}\ }}$ is

Question

Dr. Abubacker · Accepted Answer

(b)
Given, $sin\ (x + y) + \cos{(x + y) = \log{(x + y)}}$
On differentiating w.r.t. $x$, we get
$\cos{(x + y)\left( 1 + \frac{dy}{dx} \right) - \sin{(x + y)\left( 1 + \frac{dy}{dx} \right)}}$
$= \frac{1}{(x + y)}\left( 1 + \frac{dy}{dx} \right)$
$\Rightarrow 1 + \frac{dy}{dx} = 0\ \  \Rightarrow \ \ \frac{d^{2}y}{dx^{2}} = 0\ \ \ \ \$

Q. If $\sin{(x + y) + \cos(x + y) = \log{(x + y),\ \ \ then\frac{d^{2}y}{dx^{2}}\ }}$ is

Explanation

Reviewed by Dr. Abubacker

Want more practice?