If $y = cos(\sin{x^{2}),\ \ then\ at\ x = \sqrt{\frac{\pi}{2}},\frac{dy}{dx}\ }$is equal to

Question

Dr. Abubacker · Accepted Answer

(d)
$\ \ \because\ \ \ \ \ \ \ y = cos(\sin{x^{2})}$
$\ 	herefore\ \ \ \ \ \ \frac{dy}{dx} = - \sin{(\sin{x^{2})\cos{x^{2}.2x}}}$
At $x = \ \sqrt{\frac{\pi}{2}},\frac{dy}{dx} = - \sin\left( \sin\frac{\pi}{2} ight)\cos{\frac{\pi}{2}.2.\sqrt{\frac{\pi}{2}}}$
$= 0\ \ \ \ \left\lbrack \because\cos{\frac{\pi}{2} = 0} ightbrack$

Q. If $y = cos(\sin{x^{2}),\ \ then\ at\ x = \sqrt{\frac{\pi}{2}},\frac{dy}{dx}\ }$is equal to

Explanation

Reviewed by Dr. Abubacker

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