Q. If $2x^{2} - 3xy + y^{2} + x + 2y - 8 = 0,\ then\frac{dy}{dx}$ is equal to

A) $\frac{3y - 4x - 1}{2y - 3x + 2}$
B) $\frac{3y + 4x + 1}{2y + 3x + 2}$
C) $\frac{3y - 4x + 1}{2y - 3x - 2}$
D) $\frac{3y - 4x + 1}{2y + 3x + 2}$
Explanation

(a)
On differentiating given equation w.r.t. $x,$ we get
$4x - 3x\ \frac{dy}{dx} - 3y + 2y\frac{dy}{dx} + 1 + 2\frac{dy}{dx} - 0 = 0$
$\Rightarrow \ \frac{dy}{dx} = \frac{3y - 4x - 1}{2y - 3x + 2}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.