If $e^{y + e^{y + \ldots\infty}},\ x 0$, then $\frac{dy}{dx}$ is

Question

If $e^{y + e^{y + \ldots\infty}},\ x > 0$, then $\frac{dy}{dx}$ is

Dr. Abubacker · Accepted Answer

(c)
Given, $x = e^{y + x}$
$\Rightarrow {\ \ log\ }{x =}\ (y + x)\ \  \Rightarrow \ \ \frac{1}{x} = \frac{dy}{dx} + 1$
$\Rightarrow \ \frac{dy}{dx}$ = $\frac{1 - x}{x}$

Q. If $e^{y + e^{y + \ldots\infty}},\ x > 0$, then $\frac{dy}{dx}$ is

Explanation

Reviewed by Dr. Abubacker

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