Q. $\sin\left( \frac{1}{2}\cos^{- 1}\frac{4}{5} \right)$ is equal to

A) $- \frac{1}{\sqrt{10}}$
B) $\frac{1}{\sqrt{10}}$
C) $- \frac{1}{10}$
D) $\frac{1}{10}$
Explanation

(b)
$\sin\left( \frac{1}{2}\cos^{- 1}\frac{4}{5} \right)$
Now, put $\frac{4}{5} = \cos{2\theta}$
$\therefore\ \sin\left( \frac{1}{2} \times 2\theta \right)$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = \sin{\theta = \sqrt{\frac{1 - \cos{2\theta}}{2}}}$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = \sqrt{\frac{1 - \frac{4}{5}}{2}}$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = \sqrt{\frac{1}{5 \times 2}}$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = \frac{1}{\sqrt{10}}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.