(c)
Given, two angles of triangle are $\tan^{- 1}2$ and $\tan^{- 1}3.$
Let third angle be $\theta$. Then,
$\tan^{- 1}{2 + \tan^{- 1}{3 + \theta = 180{^\circ}}}$
$\Rightarrow \ \ \ \ \ \tan^{- 1}{\left( \frac{2 + 3}{1 - 2 \times 3} \right) = 180{^\circ} - \theta}$
$\Rightarrow \ \ \ \ \frac{5}{- 5} = \tan{(180{^\circ} - \theta) = - \tan\theta}$
$\Rightarrow \ \ \ \ \ \ \tan{\theta = 1 = \tan\frac{\pi}{4}}$
$\Rightarrow \ \ \ \ \ \ \ \ \ \ \ \ \ \ \theta = \frac{\pi}{4}$