Q. The value of $\sin^{- 1}{\left( \frac{\sqrt{3}}{2} \right) - \sin^{- 1}\left( \frac{1}{2} \right)}$ is
A) $45{^\circ}$
B) $90{^\circ}$
C) $15{^\circ}$
D) $30{^\circ}$
Explanation
(d)
$\sin^{- 1}{\left( \frac{\sqrt{3}}{2} \right) - \sin^{- 1}{\left( \frac{1}{2} \right) = \frac{\pi}{3} - \frac{\pi}{6} = \frac{\pi}{6} = 30{^\circ}}}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.