(d) Since, $2\cos^{- 1}{x = \cos^{- 1}{(2x^{2} - 1)}}$ Therefore, $2\cos^{- 1}{0.8 = \cos^{- 1}{(2 \times 0.64 - 1) = \cos^{- 1}{(0.28)}}}$ $\Rightarrow \ \cos{(2cos^{- 1}0.8)} = \cos{\left( \cos^{- 1}{0.28} \right) = 0.28}$
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Ph.D. in Physics with 19+ years of teaching experience.