$\sin^{- 1}{\frac{4}{5} + 2 an^{- 1}\frac{1}{3}}$ is equal to

Question

$\sin^{- 1}{\frac{4}{5} + 2	an^{- 1}\frac{1}{3}}$ is equal to

Dr. Abubacker · Accepted Answer

(c)
$\sin^{- 1}{\frac{4}{5} + 2	an^{- 1}{\frac{1}{3} = \sin^{- 1}{\frac{4}{5} + 	an^{- 1}\frac{2\left( \frac{1}{3} ight)}{1 - \left( \frac{1}{2} ight)^{2}}}}}$
$= \sin^{- 1}{\frac{4}{5} + 	an^{- 1}{\frac{3}{4} = \sin^{- 1}{\frac{4}{5} + \cos^{- 1}{\frac{4}{5} = \frac{\pi}{2}}}}}$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \left\lbrack \because\sin^{- 1}{x + \cos^{- 1}{x = \frac{\pi}{2}}} ightbrack$

Q. $\sin^{- 1}{\frac{4}{5} + 2\tan^{- 1}\frac{1}{3}}$ is equal to

Explanation

Reviewed by Dr. Abubacker

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