(b) $\therefore\cos^{- 1}{\frac{3}{5} - \sin^{- 1}{\frac{4}{5} = \cos^{- 1}x}}$ $\Rightarrow \sin^{- 1}{\frac{4}{5} - \sin^{- 1}{\frac{4}{5} = \cos^{- 1}x}}$ $\Rightarrow \cos^{- 1}{x = 0 \Rightarrow x = \cos 0 = 1}$ $\therefore x = 1$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.