Q. The equation $\lbrack 1\ x\ y\rbrack\begin{bmatrix} 1 & 3 & 1 \\ 0 & 2 & - 1 \\ 0 & 0 & 1 \end{bmatrix}\begin{bmatrix} 1 \\ x \\ y \end{bmatrix} = \lbrack 0\rbrack$ has (i)for $y = 0$(p) rational roots (ii) for $y = - 1$(q) irrational roots (r) integral roots Then (i)(ii)

A) (p) (r)
B) (q) (p)
C) (p) (q)
D) (r) (p)
Explanation

(c)
$\begin{bmatrix}
1 & x & y
\end{bmatrix}\begin{bmatrix}
1 & 3 & 1 \\
0 & 2 & - 1 \\
0 & 0 & 1
\end{bmatrix} = \begin{bmatrix}
1 \\
x \\
y
\end{bmatrix} = 10$
$\Rightarrow \lbrack 1\ \ \ 3 + 2x\ \ \ 1 - x + y\rbrack\begin{bmatrix}
1 \\
x \\
y
\end{bmatrix} = \lbrack 0\rbrack$
$\Rightarrow \left\lbrack 1 + 3x + 2x^{2} + y - xy + y^{2} \right\rbrack = \lbrack 0\rbrack$
$\Rightarrow 2x^{2} + y^{2} + y + 3x - xy + 1 = 0$
If $y = 0$,$2x^{2} + 3x + 1 = 0$
$\Rightarrow (2x - 1)(x + 1) = 0$
$\Rightarrow x = - \frac{1}{2},\ - 1$(rational roots)
If $y = - 1,\ 2x^{2} + 4x + 1 = 0$
$\Rightarrow x = \frac{- 4 \pm \sqrt{12}}{4} = \frac{- 2 \pm \sqrt{3}}{2}$ (irrational roots)

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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