Q. If matrix $A$ is given by $A = \begin{bmatrix} 6 & 11 \\ 2 & 4 \end{bmatrix},$ then the determinant of$A^{2005} - 6A^{2004}$ is

A) $2^{2006}$
B) $( - 11)^{2005}$
C) $- 2^{2005} \bullet 7$
D) $( - 9)^{2004}$
Explanation

(b)
$\left| A^{2005} - 6A^{2004} \right| = |A|^{2004}|A - 6I|$
$2^{2004}\left| \begin{matrix}
0 & 11 \\
2 & - 2
\end{matrix} \right| = ( - 22)2^{2004} = ( - 11)(2)^{2005}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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