Q. In a third order determinant, each element of the first column consists of sum of two terms, each element of the second column consists of sum of three terms and each element of the third column consists of sum of four terms. Then, it can be decomposed into $n$ determinant, where $n$ has the value
A) 1
B) 9
C) 16
D) 24
Explanation
(d)
Since, the first column consists of sum of two terms, second column consists of sum of three terms and third column consists of sum four terms.
$\therefore n = 2 \times 3 \times 4 = 24$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.